Angle ABC has point E on ray BA and point D on ray BC. Points E and D are equidistant from point B. To bisect angle ABC, which o
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The angle of B is 56.2 degrees
<em><u>Solution:</u></em>
Given is a right angled triangle ABC
From given figure,
AB = 9
CB = 5
We have to find the angle of B
Let the angle of B be
By definition of cosine,
Here, adjacent = CB and hypotenuse = AB
Therefore,
Taking cos inverse on both sides,
Thus the angle of B is 56.22 degrees
(On the far left, it says 140 at the top and then 5 to the left of 28)
The answer is 35, let me know if you can't read anything or have any questions. Hope this helped :)
The answer is 35, let me know if you can't read anything or have any questions. Hope this helped :)