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Maru [420]
2 years ago
13

Hrfbvbwknfiljwvnilkjlfb klbwejb3

Mathematics
2 answers:
NNADVOKAT [17]2 years ago
7 0

Answer:

v                fccccccccccccccg

Step-by-step explanation:

aleksandr82 [10.1K]2 years ago
5 0
7 because the circumference is 22
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Unit 3 homework 2 geometry
ioda
Where is the question?
6 0
2 years ago
Melissa's chocolate bar is 77% cocoa. If the weight of the chocolate bar is 92 grams, how many grams of
Elena L [17]

Answer:

70.8

Step-by-step explanation:

77% is the same as 0.77 so
92 * 0.77 = 77% of 92
92 * 0.77 = 70.84
rounded to the nearest tenth
70.8

7 0
2 years ago
Read 2 more answers
Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

\frac{2+2cosA  }{sinA(1+cosA)} \\\\

\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

3 0
2 years ago
Write a story about elevation that this expression could represent: 56 + (-56)
Ostrovityanka [42]

The correct statement that represents the expression is:

  • An object moves towards the east (positive direction )at a distance of 56m and west (negative direction) at the same distance, the total displacement of the object is 0m

Given the expression 56 + (-56).

  • We can see that this is an inverse rule where a value and its negative are added together.

Let us assume the values are distance covered by an object.

The correct statement that represents the expression is:

  • An object moves towards the east (positive direction )at a distance of 56m and west (negative direction) at the same distance, the total displacement of the object is 0m

This show that  56 + (-56) = 56 - 56 = 0

Learn more on inverses here: brainly.com/question/17130744

7 0
2 years ago
sheldon bought 4 1/2 kg of plant food. he uses 1 2/3 kg on his strawberry plant and used 1/4 kg for his tomato plant. how many k
fenix001 [56]

Answer:

Sheldon have left 2\frac{7}{12}\ kg of food.

Step-by-step explanation:

Quantity of food = 4\frac{1}{2}=\frac{9}{2} kg

Quantity used on strawberry plant = 1\frac{2}{3} = \frac{5}{3}\ kg

Quantity used on tomato plant = \frac{1}{4}\ kg

Food left = Total - used on strawberry - used on tomato

Food left = \frac{9}{2}-\frac{5}{3}-\frac{1}{4}

Food left = \frac{54-20-3}{12} = \frac{31}{12}

Food left = 2\frac{7}{12}\ kg

Therefore,

Sheldon have left 2\frac{7}{12}\ kg of food.

4 0
2 years ago
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