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3 years ago

The inequality x + 2y2 3 is satisfied by point (1, 1). True False

Mathematics

2 answers:

Stolb23 [73]3 years ago

8 0

Answer: true

Step-by-step explanation: because i learned last year in my accelerated math class about this and we did a quizlet on it and it had a question like that on the quiz.

Amanda [17]3 years ago

7 0

I believe that the answer is true.

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Find the probability of a least one birthday match among a group of 44 people.

Cerrena [4.2K]

Answer:

0.1137= 11.37%

Step-by-step explanation:

Assuming there are 365 days in one year and every people have 1 birthday, then the chance for two people to have the same birthday is 1/365 and the chance they are not is 364/365. We are asked the chance for at least one match among 44 people. The opposite of the condition is that we have 0 matches and easier to calculate. The calculation will be:

P(X>=1)= ~P(X=0) = 1

P(X>=1)=- P(X=0)

P(X>=1)=1 - (364/365)^44

P(X>=1)=1- 0.8862

P(X>=1)=11.37%

3 0

3 years ago

Micah mixed 3 ounces of yellow paint with 5 ounces of blue paint. What is the ratio of blue paint to the total amount of paint t

kaheart [24]

5:8
3+5=
8 (all ounces added)
5(ounces of blue)

6 0

3 years ago

Read 2 more answers

In tuv y is centroid if yw=5b and ty=4b+14 find tw

stellarik [79]

your right Step-by-step explanation:

3 0

3 years ago

A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hot dogs and 13 dozen

kicyunya [14]

Answer:

1 hot dog costs $0.75

1 bratwurst costs $1.35

Step-by-step explanation:

Let x and y be the price per dozen of hot dogs and bratwursts respectively.

The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60

8x + 13y = 282.60

The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00

10x + 15y = 333

and we have the linear system

8x + 13y = 282.60

10x + 15y = 333

which can be written in matrix form as

$\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}282.60\\333\end{array}\right)$

The solution would be given by

$\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}\left(\begin{array}{c}282.60\\333\end{array}\right)$

We have

$\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)$

hence

$\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)\left(\begin{array}{c}282.60\\333\end{array}\right)=\left(\begin{array}{c}9\\ 16.2\end{array}\right)$

Now,

if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75

if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35

4 0

3 years ago

Add the two expressions. -y - 5 and 3y + 2

Alika [10]

-y - 5 + 3y + 2

= 2y - 3

-----------------------

5 0

4 years ago

Read 2 more answers