Ask question

Ask question

All categories

4 years ago

12

How many real number roots does the equation have? Use the discriminant. 3x^2-6x+3=0

1 answer:

tresset_1 [31]4 years ago

4 0

We know that
in a quadratic equation of the form
ax²+bx+c=0
the discriminant is
D=b²-4ac
if D> 0 <span>then there are two real number solutions
if D=0 </span><span>then there's only one real number solution.
if D< 0 </span><span>then there are two complex number solutions

in this problem
we have
</span>3x²<span>-6x+3=0
a=3
b=-6
c=3
so
</span>D=b²-4ac-----> D=(-6)²-4*(3*3)----->D=36-36------->D=0

therefore
there's only one real number solution

You might be interested in

help!! i couldn’t fit the words in here but the words are, “you are riding your bike up Elm Trail towards Deer Trail. You plan t

NNADVOKAT [17]

Answer:

left

Step-by-step explanation:

basta left XD

3 0

3 years ago

Evaluate 2xy when x = -<br> and y = 3.<br> The value of the expression is<br> ]

Volgvan

2(-1/4)(3)

2 * -1/4 = -0.5

-0.5 * 3 = -1.5

-1.5 or -1 1/2

8 0

3 years ago

Please can anyone help?

Elena L [17]

Answer:

9/5x^3

Step-by-step explanation:

i hope that is the answer

7 0

3 years ago

A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of

hram777 [196]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ <u>Ratio of two angles are 6:13.</u>

So, let the one angle be $\sf{6x}$ and another be $\sf{13x.}$

As we know that,

Sum of all interior angles of a quadrilateral = $\sf\pink{360°.}$

So let's sum up the given angles,

$\rightarrow$ $\sf{222°+81°+6x+13x \:=\: 360°}$

$\rightarrow$ $\sf{303+19x \:=\: 360°}$

$\rightarrow$ $\sf{19x \:=\: 360-303}$

$\rightarrow$ $\sf{19x \:=\: 57}$

$\rightarrow$ $\sf{x \:=\: \frac{19}{57}}$

$\rightarrow$ $\sf{x \:=\: 3}$

Hence, $\sf{x \:=\: 3}$

So, First angle $\sf{= \:6x\: = \:6×3 \:=}$ $\sf\purple{18°.}$

Second angle $\sf{= \:13x\: = \:13×3 \:=}$ $\sf\purple{39°.}$

_________________________________

Hope it helps you:)

3 0

3 years ago

Cot^2x csc^2x + 2 csc^2x –cot^2 = 2

kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

4 0

4 years ago