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garri49 [273]
3 years ago
12

How many real number roots does the equation have? Use the discriminant. 3x^2-6x+3=0

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0
We know that
in a quadratic equation of the form
ax²+bx+c=0
the discriminant is
D=b²-4ac
if D> 0 <span>then there are two real number solutions
if D=0 </span><span>then there's only one real number solution.
if D< 0 </span><span>then there are two complex number solutions

in this problem
we have
</span>3x²<span>-6x+3=0
a=3
b=-6
c=3
so 
</span>D=b²-4ac-----> D=(-6)²-4*(3*3)----->D=36-36------->D=0

therefore
there's only one real number solution
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