Answer:
slope =4
Step-by-step explanation:
from, y=mx + c
where m is slope
Answer:
![\$1.09](https://tex.z-dn.net/?f=%5C%241.09)
Step-by-step explanation:
All the costs mentioned here are before tax
Let cost of junior bacon cheese burger be ![x](https://tex.z-dn.net/?f=x)
Cost of large fries be ![y](https://tex.z-dn.net/?f=y)
Heather's order cost 12.50
![6x+4y=12.5\quad\ldots (i)](https://tex.z-dn.net/?f=6x%2B4y%3D12.5%5Cquad%5Cldots%20%28i%29)
Sarah's order cost 13.70
![3x+7y=13.7\quad\ldots (ii)](https://tex.z-dn.net/?f=3x%2B7y%3D13.7%5Cquad%5Cldots%20%28ii%29)
Multiply
by ![2](https://tex.z-dn.net/?f=2)
![6x+4y=12.5](https://tex.z-dn.net/?f=6x%2B4y%3D12.5)
![6x+14y=27.4](https://tex.z-dn.net/?f=6x%2B14y%3D27.4)
Subtracting the equations we get
![-10y=-14.9\\\Rightarrow y=\dfrac{14.9}{10}\\\Rightarrow y=1.49](https://tex.z-dn.net/?f=-10y%3D-14.9%5C%5C%5CRightarrow%20y%3D%5Cdfrac%7B14.9%7D%7B10%7D%5C%5C%5CRightarrow%20y%3D1.49)
Cost of large fries is ![\$1.49](https://tex.z-dn.net/?f=%5C%241.49)
![6x+4y=12.5\\\Rightarrow x=\dfrac{12.5-4y}{6}\\\Rightarrow x=\dfrac{12.5-4\times 1.49}{6}\\\Rightarrow x=1.09](https://tex.z-dn.net/?f=6x%2B4y%3D12.5%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B12.5-4y%7D%7B6%7D%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B12.5-4%5Ctimes%201.49%7D%7B6%7D%5C%5C%5CRightarrow%20x%3D1.09)
Cost of junior bacon cheeseburger before tax is
.
Total amount of money received by David for working at his father's store = $50
Amount of money spent by David at the movies = $20
Amount of money spent by David buying comics books = $10
Amount of money spent by David buying candy = $5
Then
Total amount spent by David = (20 + 10 + 5) dollars
= 35 dollars
Amount of money saved by David = (50 - 35 ) dollars
= 15 dollars
So
The ratio of the amount of money David
spent to the amount of money David saved = 35:15
= 7:3
So the ratio of the amount of money David spent to the amount of money David saved is 7:3
$50+$10 (The coupon)=$60 to spend
$60/12=5 uniform shirts.
Step-by-step explanation:
<h2>
<em><u>St3-623t+4</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=ds</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=dsdt</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=dsdtSo 3t²12 + 3 = v</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =6t - 12 = 0</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =6t - 12 = 0t=2s</u></em></h2><h2 /><h2>
<em><u>St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =6t - 12 = 0t=2sv=3(2)² - 12 x 2+3=-9ms-1</u></em></h2>