HCl ----------> H(+) + Cl(-)
0,0045-x.........x...........x
0..................0,0045...0,0045
pH = -log[H+]
pH = -log[0,0045]
pH = 2,347
pOH = 14-pH
pOH = 14-2,347
pOH = 11,653
pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-11,653
[OH-] = 2,2233·10^-12 mol/dm³
Answer: Thus the volume of the balloon at that new location is 
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.995 atm
= final pressure of gas = 0.720 atm
= initial volume of gas = 
= final volume of gas = ?
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
Thus the volume of the balloon at that new location is
Answer:
bond angles of 120 degrees.
Answer:
12.044 X 10^23 molecules of NaOH
Explanation:
because NaOH is an ionic bond, we should be asking how many <em>formula units </em> are in 2 moles of NaOH, there are 0 molecules since NaOH is measured in formula units.
but for the sake of the problem I'll assume NaOH is measured in molecules
for every mol of something there are 6.022 X 10^23 of something of that something.
so there are 6.022 X 10^23 molecules for every mol of NaOH
that means we have 2 X 6.022 X 10^23 molecules in 2 moles of NaOH = 12.044 X 10^23 molecules of NaOH
