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3 years ago

An electromagetic wave can only move through _____. a Air b Water c Empty space d Land

Chemistry

2 answers:

kompoz [17]3 years ago

6 0

Your answer is going to be A

jok3333 [9.3K]3 years ago

3 0

The answer is a) air

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What is the usable form of nitrogen that is found in the ground?

laila [671]

Nitrate

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3 years ago

El agua oxigenada se descompone rápidamente en agua y oxígeno cuando se le agrega una peueña cantidad de dióxido de manganeso, q

katovenus [111]

Answer:

IDK

Explanation:

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3 years ago

What function does residual CO2 serve

Luba_88 [7]

The function does residual Co2 plays big part and in maintaining the body’s homeostasis. The addition of respiratory to reserve volume or residual volume. The lung is the one that who protect the organs, so in exchange of oxygen and carbon dioxide.

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3 years ago

. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r

Tom [10]

Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

Explanation : Given,

Wavelength = $435.8nm=435.8\times 10^{-9}m$

conversion used : $1nm=10^{-9}m$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength = $435.8\times 10^{-9}m$

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}$

$E=4.56\times 10^{-19}J$

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

3 0

3 years ago

A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa)?

AleksAgata [21]

<h3><u>Answer;</u></h3>

= 3032.15 kPa

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

= (5 × 0.08206 × 547)/7.5 L

= 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

<u>= 3032.15 kPa</u>

3 0

3 years ago