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BigorU [14]
1 year ago
7

choose a reasonable mechanism for the formation of cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric aci

d.
Chemistry
1 answer:
vagabundo [1.1K]1 year ago
4 0

The reasonable mechanism for the formation of cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric acid is Friedel craft alkylation.

In the Friedel craft alkylation cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric acid. in the first step the cyclohexene produced carbocation in the presence of sulfuric acid by protonation. in the second step the `the carbocation undergoes nucleophilic by the benzene ring and produced cyclohexylbenzene. this is the mechanism  followed in the formation of the cyclohexylbenzene by the Friedel craft alkylation.

Thus, The reasonable mechanism for the formation of cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric acid is Friedel craft alkylation.

To learn more about Friedel craft alkylation here

brainly.com/question/17330247

#SPJ4

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After mixing the solutions in a separatory funnel, the stopper should be ________and the liquid should be ________and the layers
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Answer:

The answer is below

Explanation:

The separation technique is used for separating immiscible liquids.

When separating, the stopper has to be removed when draining the lower layer so as to prevent a vacuum. If vacuum is allowed, the draining rate will reduce and stop.

The liquid should be mixed by shaking the funnel and then opening the stopcock so as the vent out gases.

When near interface between the layers, you should set your eye level so that you do not drain up to the second layer.

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After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.

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Sulfuric acid dissolves aluminum metal according to the following reaction:
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Answer:

m_{H_2SO_4}=81.7gH_2SO_4

m_{H_2}=1.67gH_2

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

2Al (s) + 3H_2SO_4 (aq)\rightarrow  Al _2(SO4)_3 (aq) + 3H_2 (g)

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2

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