6.022 x 10 23 titanium atoms
In 47.88 grams of titanium, there is one mole, or 6.022 x 1023 titanium atoms.
Hope this helps :)
<span>0.38
You first calculate the total moles by dividing the grams by molecular weight:
45 g N2 / 28.02 g/mol = 1.6 mol N2
40 g Ar / 39.95 g/mol = 1.0 mol
Then you divide the moles of Ar by the total number of moles:
1.0 / (1.6 + 1.0) = 0.38 mol fraction</span>
Answer: The balanced equation is
.
Explanation:
The given reaction equation is as follows.

Number of atoms present on reactant side are as follows.
- Li = 1
- H = 1
= 1
Number of atoms present on product side are as follows.
- Li = 1
- H = 2
= 1
To balance this equation, multiply Li by 2 and
by 2 on reactant side. Also, multiply
by 2 on product side.
Hence, the equation can be rewritten as follows.

Now, number of atoms present on reactant side are as follows.
- Li = 2
- H = 2
= 2
Number of atoms present on product side are as follows.
- Li = 2
- H = 2
= 2
As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is
.
Molar mass:
H₂O = 18.0 g/mol
O₂ = 32.0 g/mol
<span>C</span>₅<span>H</span>₁₂<span> + 8 O</span>₂<span> -> 5 CO</span>₂<span> + 6 H</span>₂<span>O
</span>
8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O
mass O₂ = 108 x 8 x 32 / 6 x 18
mass O₂ = 27648 / 108
mass O₂ = 256 g
hope this helps!