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andreev551 [17]
3 years ago
8

Is salt water solution a homogeneous mixture

Chemistry
2 answers:
GuDViN [60]3 years ago
8 0

Answer:

yes, it is a homogeneous mixture because the different parts cannot be seen.

Explanation:

umka21 [38]3 years ago
4 0
Yes it is . . . . . .
You might be interested in
One mole of titanium contains how many atoms
vitfil [10]

6.022 x 10 23 titanium atoms

In 47.88 grams of titanium, there is one mole, or 6.022 x 1023 titanium atoms.

Hope this helps :)

8 0
3 years ago
A solution contains 45 grams of nitrogen gas and 40 grams of argon. What is the mole fraction of argon in this solution?
Katarina [22]
 <span>0.38 

You first calculate the total moles by dividing the grams by molecular weight: 
45 g N2 / 28.02 g/mol = 1.6 mol N2 
40 g Ar / 39.95 g/mol = 1.0 mol 

Then you divide the moles of Ar by the total number of moles: 
1.0 / (1.6 + 1.0) = 0.38 mol fraction</span>
8 0
4 years ago
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
3 years ago
using the equation, C5H12 + 8O2 -&gt; 5CO2 + 6H2O, if 108 g of water are produced, how many grams of oxygen were consumed?
vodomira [7]
Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

<span>C</span>₅<span>H</span>₁₂<span> + 8 O</span>₂<span> -> 5 CO</span>₂<span> + 6 H</span>₂<span>O
</span>
8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

3 0
3 years ago
What is a substance made of 2 or more elements called
Wittaler [7]
It’s called a compound
7 0
3 years ago
Read 2 more answers
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