After careful deliberation, I took the opportunity to find the answers for you.
Answers:
1) _2_Al + _6_HC2H3O2 ->_2_Al(C2H3O2)3 + _3_H2
3) _1_Fe + _2_HBr -> _1_H2 + _1_FeBr2
5) _2_NaOH + _1_ H2SO4 -> _1_Na2SO4 + _2_H2O
7) _2_N2O -> _2_N2 + _1_ O2
9) _1_P4O6 + _2_O2 -> _1_P4O10
11) _2_Mg + _2_CH3COOH -> _2_Mg(CH3COO)2 + _1_H2
13) _2_Al3 + _18_HCl -> _9_H2 + _6_AlCl3
15) _4_KOH + _2_H2SO4 -> _4_H2O + _2_K2SO4
17) _2_NH3 -> _1_N2 + _3_H2
19) _2_SO2 + _1_O2 -> _2_SO3
DONE! *breathes heavily* Alright, after like 30 minutes, these are the answers for your problem.
Hope this helps! :)
<span>what volume of ammonia must you measure?
1.50 moles NH3 ( 22.4 L / 1 mole ) = 33.6 L NH3 should be measured
</span><span>how many molecules of nacl are in 23.40 grams nacl
23.40 g NaCl ( 1 mol / 58.44 g) (6.022 x 10^23 molecules / 1 mol ) = 2.4113 x 10^23 molecules
Hope these answer the questions. Have a nice day.</span>
Answer:
"This conversions relies on the fact that a mole of gas at STP has a volume of 22.4 L. It is important to note, however, that if the conditions of the gas are different this conversion will NOT work. Under those conditions you must use the ideal gas law to convert between moles and liters."
At 40 degrees Celsius, approximately 78 grams of potassium bromide can be dissolved.
the answer is 1.44607 x 10^23. multiply 5.548 x 6.022x10^23(arogados number) over 231.04(the molar mass of Th)