Write a note on particle nature of matter

How do I write an introduction in chemistry report? the experiment is seeing which ionic compounds produce precipitates.

tensa zangetsu [6.8K]

Answer:you can write the definition of some main words in your experiment and the main idea of the experiment and how the experiment is to talk about.

Explanation:

3 0

3 years ago

On the following chemical equation, label the acid, the base, the

beks73 [17]

Answer:

HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)

Acid Base Conj. acid Conj. base

Explanation:

The equation is:

HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)

This is the typical equilibrium for a weak acid. It would complete if we notice the Ka.

HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq) Ka

1 mol of hypothetic HX acid react to 1 mol of water in order to release a proton and make hydronium and generate the X⁻ anion.

HX will be the acid, in this case a weak one and water will be the base. Water is able to accept a proton to make itslef hydronium

Hydronium is the conjugate acid.

The X⁻ will be the conjugate strong base.

This ion can generate the acid form again, that's why it is strong, because it can make hydrolisis.

X⁻ (aq) + H₂O (l) ⇄ HX (aq) + OH⁻(aq) Kb

In this case, the anion will be the conjugate base which it takes a proton from water (acid form) to make a conjugate acid, the HX and a conjugate base, OH⁻

3 0

3 years ago

In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i

fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

Step 1: Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

7 0

3 years ago

ILL GIVE YOU BRAINLIEST <3

Paha777 [63]

Answer:

Should be a 15 imo

Explanation:

N is one, 4H = 4, S 2 because of the 2 and O 8 because of the 4 and the 2 before the S.

5 0

3 years ago

How many moles of naoh will react with 13.5 moles of k3po4

Alona [7]

Answer: 40.5 mol

Explanation:

Since this is a double replacement reaction, the unbalanced equation is something like follows:

$\text{K}_{3}\text{PO}_{4}+\text{NaOH} \longrightarrow \text{KOH}+\text{Na}_{3}\text{PO}_{4}$

Balancing this equation,

$\text{K}_{3}\text{PO}_{4}+3\text{NaOH} \longrightarrow 3\text{KOH}+\text{Na}_{3}\text{PO}_{4}$

From this equation, we can conclude that for every 3 moles of sodium hydroxide consumed, 1 mole of potassium phosphate is consumed.

This means the answer is 13.5(3)=40.5 mol

8 0

2 years ago

Write a note on particle nature of matter​

Write a note on particle nature of matter