Quadratic Formula is (-b ±√(b²-4ac))/2a
With that being said:
y=2x²-5x-1 is in the correct form of ax²+bx+c
Now just plug in:
5±√(25-4(2 x-1))
5± √25+8
(5±√33)/2(2)
Answer is D
100% Sure
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Hope that helped!
Answer:

Step-by-step explanation:
we know that
The standard equation of a horizontal parabola is equal to

where
(h,k) is the vertex
(h+p,k) is the focus
In this problem we have
(h,k)=(0,0) ----> vertex at origin
(h+p,k)=(-4,0)
so
h+p=-4
p=-4
substitute the values


Answer:
x+9=4x-4
=) x -4x = -4-9
=) -3x = -13
=) x = 13/3
It is not the form of ax 2 +bx +c =0
It's a linear function with a slope 0.
It's a horizontal line (look at the picture).