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AlladinOne [14]
3 years ago
12

Does anyone know how to do this?

Chemistry
1 answer:
Sedaia [141]3 years ago
4 0

I suppose that the question ask the following:

What is the mass of a sample, composed of C₃H₅N₃O₉ molecule, that contains 100 g carbon?

First we calculate the molecular mass of our molecule  C₃H₅N₃O₉.

molecular mass = 12 × 3 + 1 × 5 + 14 × 3 + 16 × 9 = 227 g/mol

Now we devise the following reasoning:

if          227 g of our molecule contains 27 g of carbon

then      X    g of our molecule contains 100 g carbon

X = (100 × 227) / 27 = 840.7 g

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This is an example of a mixture that will separate______.
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B is the correct answer

6 0
4 years ago
4. Quando se obtém a potência máxima da célula, o valor indicado no amperímetro, na unidade SI, está no intervalo: (A) [3,1; 3,2
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8 0
3 years ago
What is the intermolecular force of NH3
Dominik [7]
ANSWER:
London dispersion and hydrogen bonds.


EXPLANATION :
Every molecule experiences London dispersion as an intermolecular force.since the ammonia ion has hydrogen atoms bonded to nitrogen,a very electronegative atom,the molecule is also polar since the nitrogen atom more strongly pulls on the electrons from the hydrogen atoms than the hydrogens themselves do.

This effect is similar to that water,where the oxygen pulls the electrons of the hydrogen atoms with a greater magnitude,resulting in the oxygen having a partial negative charge and the hydrogens having a partial positive charge relative to each other.

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I HOPE IT HELPS:)
3 0
4 years ago
How many moles of k3po4 can be formed when 4.4 moles of h3po4 react with 3.8 moles of koh? h3po4 + koh yields h2o + k3po4 be sur
schepotkina [342]

the balanced chemical equation for the reaction is as follows

H₃PO₄ + 3KOH ---> K₃PO₄ + 3H₂O

stoichiometry of H₃PO₄ to KOH is 1:3

first we have to find which the limiiting reactant is

as the amount of product formed depends on the amount of limiting reactant present

number of H₃PO₄ moles reacted - 4.4 mol

if H₃PO₄ is the limiting reactant

1 mol of H₃PO₄ reacts with 3 mol of KOH

then 4.4 mol of H₃PO₄ reacts with - 3 x 4.4 mol = 13.2 mol of KOH

but only 3.8 mol of KOH is present

therefore KOH is the limiting reactant


stoichiometry of KOH to K₃PO₄ is 3:1

number of KOH moles reacted - 3.8 mol

therefore number of K₃PO₄ formed = number of KOH moles reacted / 3

= 3.8 mol / 3 = 1.3 mol


answer is 1.3 mol of K₃PO₄


3 0
4 years ago
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