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lukranit [14]
3 years ago
11

Ammonium phosphate NH43PO4 is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric a

cid H3PO4 with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 0.050mol of phosphoric acid. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Chemistry
1 answer:
Nataly_w [17]3 years ago
5 0

Answer:

0.050 mol

Explanation:

The reaction that takes place is:

  • H₃PO₄ + 3NH₃ → (NH₄)₃PO₄

Then we convert 0.050 moles of phosphoric acid into moles of ammonium phosphate, using the stoichiometric coefficients of the reaction:

  • 0.050 mol H₃PO₄ * \frac{1mol(NH_4)_3PO_4}{1molH_3PO_4} = 0.050 mol (NH₄)₃PO₄

Thus, the complete reaction of 0.050 moles of phosphoric acid would produce 0.050 moles of ammonium phosphate.

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Answer:

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Explanation:

For B_2H_6  :-

Mass of B_2H_6  = 296.1 g

Molar mass of B_2H_6  = 27.66 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{296.1\ g}{27.66\ g/mol}

Moles\ of\ B_2H_6= 10.705\ mol

From the balanced reaction:-

B_2H_6(g) + 3 O2_{(l)}\rightarrow 2 HBO_2_{(g)}+ 2 H_2O_{(l)}

1 mole of B_2H_6 react with 3 moles of oxygen

Thus,

10.705 mole of B_2H_6 react with 3*10.705 moles of oxygen

Moles of oxygen = 32.115 moles

Molar mass of oxygen gas = 31.998 g/mol

<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>

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