Answer:
[OH-] = 6.17 *10^-10
Explanation:
Step 1: Data given
pOH = 9.21
Step 2: Calculate [OH-]
pOH = -log [OH-] = 9.21
[OH-] = 10^-9.21
[OH-] = 6.17 *10^-10
Step 3: Check if it's correct
pOH + pH = 14
[H+]*[OH-] = 10^-14
pH = 14 - 9.21 = 4.79
[H+] = 10^-4.79
[H+] = 1.62 *10^-5
6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14
The reactants has 2 NO2 and the product has 3. So we need to make sure we have 6 on each side.
Al + 3Fe(NO2)2 -> Fe + 2Al(NO2)3
This leaves us with us just to balance the Fe And Al
2Al + 3Fe(NO2)2 -> 3Fe + 2Al(NO2)3
Hope this helped :)
Answer:
It amplifies the picture of something far away.
Explanation:
What is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C?
- (1) 9100 J
- (2) 4600 J
- (3) 1400 J
- (4) 2300 J
<u>Answer:</u>
9100 J is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C.
<u>Explanation:</u>
Given: Q = ? J
mass = 49.5 g = 0.0495 kg
T1 = 22°C
T2 = 66°C
Cp = 4.18 J/Kg°C
Q = mCpΔT
Q = (4.95)(4.18)(66 - 22)
Q = 9104 J
So 9100 J is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C.
Answer:
tomic size is the distance from the nucleus to the valence shell where the valence electrons are located. Atomic size is difficult to measure because it has no definite boundary. The electrons surrounding the nucleus exist in an electron cloud.
Explanation:
