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Svetllana [295]
4 years ago
8

a gas that exerts a pressure of 6.20 atm in a container with a volume of ___mL will exert a pressure of 9.150atm when transferre

d to a container with a volume of 322mL
Chemistry
1 answer:
Triss [41]4 years ago
8 0
 a  gas   exert  a  pressure  of 6.20   atm  in a container  with a volume  of 475.2  ml  will  exert  a  pressure of 9.150  atm  when transferred   to a  container  with a volume  of 322 ml

     Explanation
This is  calculated  using the  Boyles  law   formula
that is P1V1= P2V2
P1=6.20 atm
V1=?
P2=9.150 atm
V2=  322  ml

by  making  V1  the subject of the   formula

V1= P2V2/P1

V2  is therefore =  (9.150 atm  x322 ml) / (6.20   atm-)  = 475.2  ml
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2) N₂O; m(N) : m(O) = 2·14 : 16 = 7 : 4.

3) NO₂; m(N) : m(O) = 14 : 2·16 = 7 : 16.

4) N₂O₅; m(N) : m(O) = (2·14) : (5·16) = 7 : 20.

5) NO₄; m(N) : m(O) = 14 : (4·16) = 7 : 32.

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m(N) : m(O) = 1 : 2857/ ×7.

m(N) : m(O) = 7 : 20.

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