Answer:
x=11
Step-by-step explanation:
5x+62=3x+47+37
5x+62=3x+84
2x=22
x=11
Answer:
Step-by-step explanation:
Answer:
x=10^{\frac{2}{3}}-5
Step-by-step explanation:
Answer:
a. attached graph; zero real: 2
b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Step-by-step explanation:
p(x) = x³ + 4x² + 6x - 36
a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.
p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0
b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.
2 | 1 4 6 -36
1 6 18 0
x² + 6x + 18 = 0
Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²
√Δ = 6i
x = -6±6i/2 = 2(-3±3i)/2
x' = -3-3i
x" = -3+3i
p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Since each vector is a member of
, the vectors will span
if they form a basis for
, which requires that they be linearly independent of one another.
To show this, you have to establish that the only linear combination of the three vectors
that gives the zero vector
occurs for scalars
.
Solving this, you'll find that
, so the vectors are indeed linearly independent, thus forming a basis for
and therefore they must span
.