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3 years ago

7

A video game displays 84 frames in 4 seconds on Penelope's computer. What is the rate in frames per second?

1 answer:

svetlana [45]3 years ago

8 0

Answer: 21

Step-by-step explanation: 84/4 = 21

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I need help on these questions

Advocard [28]

For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.

for # 3:
we know A = pi r^2
We have
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04

for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92

for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582

4 0

3 years ago

Which inequalities is -5 a possible solution?

coldgirl [10]

Answer:

1st, 3rd and second last one

5 0

2 years ago

A BAG HAS 2 YELLOW CUBES 3 BLUE CUBES AND 1 YELLOW CUBE. WHAT WOULD BE THE PROBABILITY TO PULL OUT YELLOW.

Lapatulllka [165]

Answer:

1/2 <u>or</u> 0.5 <u>or</u> 50%

Step-by-step explanation:

3 + 3 = 6

3/6 = 1/2

5 0

3 years ago

Read 2 more answers

Evaluate if a=2 and b=8 6+7b-3a

VladimirAG [237]

Answer:

56

Step-by-step explanation:

6+7b-3a

Substitute:

6+7(8)-3(2)

Solve:

6+56-6

Simplify:

6+50

=56

7 0

3 years ago

Read 2 more answers

Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911

nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

$\lambda=\dfrac{1}{2}$

(a) What is the expected number of 911 calls in one hour?

$\lambda=\dfrac{1}{2}\times 60=30$

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

$\lambda=\dfrac{1}{2}\times 5=2.5$

Number of calls = 3

So, P(X=3) is given by

$P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138$

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

$P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820$

Hence, a) 30, b) 0.2138, c) 0.0820

4 0

3 years ago