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labwork [276]
3 years ago
15

According to the food chain below, which of these organisms most likely contains the least concentration of toxins (DDT) ?

Biology
1 answer:
agasfer [191]3 years ago
5 0

Answer:

Hawk

Explanation:

Dichlorodiphenyltrichloroethan which is also known as DDT is a colorless, tasteless and almost odorless crystalline chemical compound. It was originally developed as an insecticide and it causes harm to wildlife animals.

When the chemical are sprayed or gets in contact with the soil it is the terrestrial organisms such as plants and primary consumers who gets affected the most due to direct contact with the chemical.

Animals such as hawks who are arboreal and tertiary consumers from the list of options don’t get affected directly from the source of the DDT contamination which makes them least affected.

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A research team studies a large Eastern Milk Snake population in a metropark. In these snakes, gene T is one gene that affects t
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Answer:

Option E

Explanation:

As per Hardy Weinberg's second equation of equilibrium, the sum of genotype frequency for all possible genotype in a given population with two allele is equal to

p^2 + q^ 2+2pq = 1\\

Substituting the given values in above equation, we get -

0.16 + 0.64 + 0.20 =1\\ p^2+q^2+2pq= 1

Hence, second equation satisfies.

As per  Hardy Weinberg's first equation of equilibrium, sum of all allele frequencies is equal to 1

p + q=1\\\sqrt{0.16} +\sqrt{0.64} \\0.4+0.8 = 1.2\neq 1

Hence, this population is not in Hardy weinberg's equation.

After one generation, the frequency of T allele is 0.4 which is the same as that of frequency of T allele in previous generation

Also as per hardy Weinberg's theory , if a population genotype frequency sums up to 1,  it is in equilibrium if its allele frequency sum is also 1.

But here in 2004. This was not the case.

However, Weinberg has stated that the population which is not in equilibrium can reach equilibrium after one generation only with a new set of genotype frequency and allele frequencies.

Hence, in this case there is a possibility that allele and genotype frequencies have readjusted to sum  up to 1

If frequency of the T allele is 0.4

New frequency of the t  allele would be

1- 0.4\\= 0.6

and New genotype frequencies would be

p^ 2 = 0.4^2 = 0.16\\q^ 2 = (1-0.4)^2 = 0.36\\2pq = 1-0.16-0.36 = 0.48

Thus, p^ 2+q^2+2pq = 1

Hence, option E is correct

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