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3 years ago

12

The total cost of attending an AHS football game can be presented by the equation C= 5t, where C is the total cost and t is the

number of tickets purchased. How many tickets can you get for $35.00?

1 answer:

Nitella [24]3 years ago

7 0

Seven tickets, you only need to take away the "C" and substitute for $35.00 and solve for "t"

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Perform the indicated operation. 8/a - 6/a + 7/a

Jlenok [28]

Answer:

9/a

Step-by-step explanation:

8/a - 6/a + 7/a

Since the denominators are the same, we can add the numerators

8-6+7 =9

Then put it over the common denominator a

9/a

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Find the volume of a rectangle box 12cm by 15cm by 10cm

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Answer:

Step-by-step explanation:

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What is 9-(-5) please help me

elena-14-01-66 [18.8K]

9-(-5)=

9 + 5 (because - - = +)

14

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3 years ago

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$

$\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4$

$\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4$

$\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4$

Substituting the values in the series expansion gives:

$e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...$

Factoring out e⁴:

$e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right]$

<u>Taylor Series summation notation</u>:

$\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n$

Therefore:

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

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1 year ago

I paid $8.50 each for movie tickets and i spend a total of $144.50. If n, represents how many tickets i bought, write and equati

damaskus [11]

Answer:
$144.50/8.50 = n

Explanation:
The word each indicates this equation will use division. We know the total is 144.50, so that will be the number being divided. 8.50 is the number 144.50 is divided by. The quotient will be represented by the variable, n.

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