How do you factor this ?

What would the equation be if the sum of t and 2 is equal to 5 less than t

TEA [102]

Answer:

$t=\frac{3}{2}$

Step-by-step explanation:

1.

$t+2=5-t$

2.

$2t+2=5$

3.

$2t=3$

4.

$t=\frac{3}{2}$

7 0

3 years ago

Sam deposits $1,000 into an account that pays 6% simple interest annually. He plans to take the money out after 3.5 years. What

lara31 [8.8K]

Well, the formula for simple interest is

$I=prt$

"I" is interest, "p" is the principal, "r" is the rate, and "t" is the time.

If you substitute the numbers, you get

$I=1,000(0.06)(3.5)$

When you multiply them together, you get

$I=210$

So, the simple interest for 3.5 years is $210.

But, in order to get the total balance, you have to add the interest and the principal together.

$B=1000+210 \\ B=1210$

So, the balance after 3.5 years is $1,210.

5 0

3 years ago

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Which expression is equivalent to x2−12x+36?

Helga [31]

Answer:

(x-6)(x-6) or (x-6)^2

Step-by-step explanation:

6 0

3 years ago

Find the angle sum of a polygon of 42 sides

Simora [160]

Answer:

In geometry, a tetracontadigon (or tetracontakaidigon) or 42-gon is a forty-two-sided polygon. (In Greek, the prefix tetraconta- means 40 and di- means 2.) The sum of any tetracontadigon's interior angles is 7200 degrees.

3 0

3 years ago

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