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Nana76 [90]
3 years ago
7

Find the angle sum of a polygon of 42 sides​

Mathematics
2 answers:
Arturiano [62]3 years ago
7 0

Hey there!   ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・

The answer is 7200 degrees. ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦

Because ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎ ⭐︎

(n-2)180

n is the number of sides in a polygon.

Here we have 42 sides:

(42-2)*180=40*180=7200

Simora [160]3 years ago
3 0

Answer:

In geometry, a tetracontadigon (or tetracontakaidigon) or 42-gon is a forty-two-sided polygon. (In Greek, the prefix tetraconta- means 40 and di- means 2.) The sum of any tetracontadigon's interior angles is 7200 degrees.

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Answer:

Step-by-step explanation:

Given:

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A.

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B.

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= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

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C.

Area of 1.9 cm pipe, Ap = πD²/4

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Velocity of the water, Vw = volumetric flowrate/area

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