Question

WHOEVER ANSWERS THIS I WILL MARK AS BRAINLIEST PLEASE HELP A bottle of sugar syrup soda had 4 ⅓ grams of sugar in it. If Tom drank 3 full bottles and 7/9 of a bottle, how many grams of sugar did he drink?

Answer 1

Answer:

$16\frac{10}{27} \mbox{g}$

Step-by-step explanation:

This is essentially a multiplication problem! We have

$4\frac{1}{3} \mbox{g sugar/bottle} \times3\frac{7}{9} \mbox{ bottles}$

Let's start by figuring out the number of grams in 3 bottles. If one bottle has 4 1/3 g of sugar, 3 bottlesshould have 4 × 3 = 12g plus another 1/3 × 3 = 1g, for a total of 12 + 1 = 13g. Taking 7/9 of 4 1/3g, we have

$4\frac{1}{3} \times\frac{7}{9}=\frac{13}{3}\times\frac{7}{9} =\frac{91}{27}=3\frac{10}{27}\mbox{g}$

Adding that to the 13g from the 3 bottles gives us a total of 13 + 3 10/27 = $16\frac{10}{27} \mbox{g}$

Answer 2

Answer:

Its 16 and $\frac{10}{27}$

Step-by-step explanation:

do $\frac{13}{3}*\frac{34}{9}$ to get $16 \frac {10}{27}$