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3 years ago

you had $22 to spend on three pretzels. After buying them you had $15.70.How much did each pretzel cost?

Mathematics

2 answers:

andreev551 [17]3 years ago

5 0

Answer:

each pretzel costs about $2.10

Step-by-step explanation:

gulaghasi [49]3 years ago

5 0

Answer: $2.10

Step-by-step explanation: 22-15.70= 6.3

This means you spent $6.30 on pretzels. Divide 6.30 by 3 to find out how much each pretzel costs. You would get 2.1 (which is written as $2.10 in money).

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5 - 3(6 - 2y)

saul85 [17]

Answer:

6y - 13

Step-by-step explanation:

5 - 3(6 - 2y)

Distribute;

5 - 18 + 6y

-13 + 6y <em>OR</em> 6y - 13

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3 years ago

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A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/25 for red, 1/20 fo

VARVARA [1.3K]

Probability helps us to know the chances of an event occurring. The probability of pulling a green or red card is 9 / 100.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

P = $\dfrac{Desired \ outcomes}{Posiible \ outcomes}$

The probabilities of different color cards being pulled are 1/25 for red, 1/20 for green, 1/15 for purple, and 1/10 for black Therefore, the probability of pulling a green or red card is,

Probability = 1/20 + 1/25

= (5 + 4) /100

= 9 / 100

Hence, the probability of pulling a green or red card is 9 / 100.

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2 years ago

Find the volume of the pyramid. Write your answer as a fraction or mixed number.

tia_tia [17]

Answer:

V=lwh /3

Step-by-step explanation:

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3 years ago

Sameera predicted that she would sell 38 blankets, but she actually sold 28 blankets. Which expression would find the percent er

antoniya [11.8K]

Solution: We are given:

Predicted Sales by Sameera $=38$

Actual Sales by Sameera $=28$

Now to find the Percent error, we have to use the below formula:

$Percent-Error= \frac{|Predicted-value - Actual-value|}{Actual-value} \times 100 \%$

$=\frac{|38-28|}{28} \times 100 \%$

$=\frac{10}{28}\times 100 \%$

$=35.71 \%$

Therefore, the percent error is $35.71 \%$

8 0

4 years ago

Read 2 more answers

Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b

trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

$6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right]$ ÷ $2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]$

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) $\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}$

( 2 ) $\sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}$

These two identities makes sin(π / 10) = $\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}$ , and cos(π / 10) = $\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}$ .

Therefore cos(2π / 5) = $\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}$ , and sin(2π / 5) = $\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}$ . Substitute,

$6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right]$ ÷ $2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]$

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

$6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right]$ ÷ $2\sqrt{2}\left[0-i\right]$

And now simplify this expression to receive our answer,

$6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right]$ ÷ $2\sqrt{2}\left[0-i\right]$ = $-\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i$ ,

$-\frac{3\sqrt{5+\sqrt{5}}}{4}$ = $-2.01749\dots$ and $\:\frac{3\sqrt{3-\sqrt{5}}}{4}$ = $0.65552\dots$

= $-2.01749+0.65552i$

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = $\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}$ , sin(2π / 5) = $\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}$ , cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

$6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}$

We know that $6\sqrt{5+\sqrt{5}} = 16.13996\dots$ and $-\:6\sqrt{3-\sqrt{5}} = -5.24419\dots$ . Therefore,

Solution : $16.13996 - 5.24419i$

Which rounds to about option b.

7 0

3 years ago