What is the SI unit of time? Asecond B. minute C. hour D. day

Explain why sodium chloride solution cannot be used as the electrolyte to produce

ira [324]

Explanation:

Because the solution only contains Na+ and Cl− ions, and water, and not the metal Na(s) . You cannot evaporate the water from the solution and hope to obtain anything but NaCl(s) .

.

Na(s) has an electron configuration of 1s^2 2s^2 2p^6 3s^1 , but Na+(aq) has an electron configuration of 1s^2 2s^2 2p^6 . That means they are not the same element, and thus, there is no straightforward way of extracting Na(s) from a NaCl (aq) solution

6 0

2 years ago

A uniform cylinder of mass 4.3 kg and radius 0.4 m rolls down a ramp inclined at an angle 0.15 radians to the horizontal. what i

tester [92]

The cylinder's acceleration is

$a=\frac{gsin}{1+\frac{I}{mrL} }$

$= 2g\frac{sin}{3}$ θ

$= \frac{2(9.8) sin (0.15 rad)}{3} \\=0.9763 \frac{m}{sec r}$

<h3>How do you determine a cylinder's acceleration?</h3>

The cylinder's complete radius, $R$ , from the center marks the contact point, therefore the torque created by friction is given by $fR = I\alpha$ , where is the rotating acceleration. This rotational acceleration's corresponding linear acceleration, $\alpha$ , is equal to $R$ . The cylinder, which has its mass concentrated in its center, triumphs in the competition, followed by the disc and the hoop, with their respective final velocities being roughly $1.4:1.2:1$ . We can also see that our findings are unaffected by the cylinders' masses.

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5 0

2 years ago

Petroleum and coal can be mined from the continental shelf. t/f

bazaltina [42]

True

Petroleum and coal can be mined from the continental shelf. Hot magma from inside the Earth seeps out from the crevices in the mid-ocean ridge. There is speculation regarding whether this is a cost-effective technique. Fossil fuels and mineral deposits can be located all throughout the continental shelf and also in some of the deepest depths of the ocean.

7 0

3 years ago

Read 2 more answers

The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the following steps:

bagirrra123 [75]

Answer:

$12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow 14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)$

Explanation:

The steps of the Ostwald process:

$4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)$

$2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g)$

$3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g)$

Combinning the equations:

$4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)$

+

$(2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g))*2$

+

$(3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g))*4/3$

=

$4 NH_3 (g)+ 4 NO (g)+ 7 O_2 (g) + 4 NO_2 (g) +4/3 H_2O (l) \longrightarrow 4 NO (g) + 6 H_2O (g) + 4 NO_2(g) + 8/3 HNO_3 (g) + 4/3 NO (g)$

Simplifying:

$4 NH_3 (g)+ 7 O_2 (g) + \longrightarrow 14/3 H_2O (l) + 8/3 HNO_3 (g) + 4/3 NO (g)$

$12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow 14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)$

The overall reaction is endothermic becuase the formation of new chemical bonds requires energy consumption.

4 0

3 years ago

Consider the reaction: 2HI(g) ⇄ H2(g) + I2(g). It is found that, when equilibrium is reached at a certain temperature, HI is 35.

Sliva [168]

Answer:

Kc = 0.075

Explanation:

The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:

α = x/M

x = M*α

x = 0.354M

For the stoichiometry of the reaction (2:1:1), the concentration of H₂ and I₂ must be half of the acid. So the equilibrium table must be:

2HI(g) ⇄ H₂(g) + I₂(g)

M 0 0 Initial

-0.354M +0.177M +0.177M Reacts

0.646M 0.177M 0.177M Equilibrium

The equilibrium constant Kc is the multiplication of the products' concentrations (elevated by their coefficients) divided by the multiplication of the reactants' concentrations (elevated by their coefficients):

$Kc = \frac{[H2]*[I2]}{[HI]^2}$

$Kc = \frac{0.177M*0.177M}{(0.646M)^2}$

$Kc = \frac{0.03133M^2}{0.41732M^2}$

Kc = 0.075

5 0

3 years ago