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3 years ago

Compounds

Chemistry

2 answers:

Mama L [17]3 years ago

7 0

Answer:

have different properties from the elements they are made from

Explanation:

Compounds have different properties from the elements they are made from. Compounds are substances composed of two or more kinds of atoms/elements joined together in a definite grouping.

The properties of a compound are distinct and different from those of the individual elements that are combined in its make-up.
There are several millions of compounds that are known.
These are derived from elements.

vfiekz [6]3 years ago

4 0

Answer:

Que?

Explanation:

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The pressure in an automobile tire filled with air is 245.0 kPa. If Po2 = 51.3 kPa, Pco2 = 0.10 kPa, and P-others = 2.3 kPa, wha

Kay [80]

Answer:

PN₂ = 191.3 Kpa

Explanation:

Given data:

Total pressure of tire = 245.0 Kpa

Partial pressure of PO₂ = 51.3 Kpa

Partial pressure of PCO₂ = 0.10 Kpa

Partial pressure of others = 2.3 Kpa

Partial pressure of PN₂ = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this problem by using this law.

P(total) = PO₂ + PCO₂ + P(others)+ PN₂

245 Kpa = 51.3 Kpa + 0.10 Kpa + 2.3 Kpa + PN₂

245 Kpa = 53.7 Kpa+ PN₂

PN₂ = 245 Kpa - 53.7 Kpa

PN₂ = 191.3 Kpa

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4 years ago

Advantages and disadvantage of chemistry

klemol [59]

Answer:

it's good because u learn about chemicals and fumes

irs bad because some smells are just horrible

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3 years ago

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Mgso4 how many of each atom exists in a molecule of epsom salts

jolli1 [7]

1 magnesium atom, 1 sulfur atom, 4 oxygen atoms.

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3 years ago

An example of a pure metal with a hexagonal close-packed arrangement is

Degger [83]

Zinc is an example of a pure metal with a hexagonal close-packed arrangement.
~Glad to help ^^

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3 years ago

A sample of cobalt has a mass of 27 g and a density of 9 g/cm^3. What would be its volume?

8_murik_8 [283]

Given ,

Mass of sample of cobalt = 27 g

density of sample of cobalt = 9g/cm^3

We know that ,

Density = mass of sample/volume of sample

From that relation ,

We can deduce the following as

Volume = mass of sample/density of sample

Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3

The volume is $\fbox{3cm cube}$

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2 years ago