The product<span> of </span>two consecutive odd<span> numbers is </span>143<span>. Find the numbers. (Hint: if the first </span>odd<span> number is x, what is the next </span>odd<span> number?) ... Ad: You enter your algebra </span>equation<span>or inequality - Algebrator solves it step-by-step while ... We </span>need two<span> numbers that add up to </span>2<span>. ... The next </span>consecutive odd integer<span> is , so</span>
Answer:
C
Step-by-step explanation:
Given
6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation
6x + 24 = 2y + 10 ( subtract 10 from both sides )
6x + 14 = 2y ( divide all terms by 2 )
3x + 7 = y, hence
y = 3x + 7 → C
<span>Width = 6
Length = 30
We know the perimeter of a rectangle is simply twice the sum of it's length and width. So we have the expression:
72 = 2*(L + W)
And since we also know for this rectangle that it's length is 6 more than 4 times it's width, we have this equation as well:
L = 6 + 4*W
So let's determine what the dimensions are. Since we have a nice equation that expresses length in terms of width, let's substitute that equation into the equation we have for the perimeter and solve. So:
72 = 2*(L + W)
72 = 2*(6 + 4*W + W)
72 = 2*(6 + 5*W)
72 = 12 + 10*W
60 = 10*W
6 = W
So we now know that the width is 6. And since we have an expression telling us the length when given the width, we can easily determine the length. So:
L = 6 + 4*W
L = 6 + 4*6
L = 6 + 24
L = 30
And now we know the length as well.</span>
Answer:
The equivalent to one over five m − 20 is one over five (m − 100) ⇒ B
Step-by-step explanation:
Let us solve the question
∵ One over five means 
∴ One over five m - 20 = m - 20
→ By using the distributive property, take one over five as a common factor
from both terms
∴ m - 20 = 
- 
→ Simplify the bracket
∵ m ÷ = m × 5 = m
∵ 20 ÷ = 20 × 5 = 100
∴ - = (m - 100)
∴ m - 20 = (m - 100)
The equivalent to one over five m − 20 is one over five (m − 100)
Answer:
wanna help, but please specify what the (2) means.
our take a picture of the problem and makes me post.
