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makvit [3.9K]
3 years ago
11

If the value of x is equal to a -6, does it make this inequality a true statement? -3-5x<-14

Mathematics
2 answers:
Rama09 [41]3 years ago
7 0
Yes it makes it a true statement because if my math is correct it will add up and the negative is not canceled. That’s only with multiplication
Alborosie3 years ago
5 0

Answer: Yes it does make the inequality a true statement

Step-by-step explanation: -3 - 5 x -6 < - 14

5 x -6 = -30

-3 - 30 = -33

-33 < -14

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The lines given by the equations y=2x and y=4x+1 are
Sav [38]

Answer:

A

Step-by-step explanation:

For lines to be parallel, their slopes need to be the same.

For lines to be perpendicular, the product of their slopes needs to be -1.

None of these conditions are met since the slopes are 2 and 4 respectively.

Sooo.... The answer must be A! :)

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3 years ago
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Emilia took a math quiz last week. She got 19 problems correct and 76 problems incorrect. What percentage did Emilia get correct
Volgvan

Answer: 20%

Step-by-step explanation:

To find the total number of problems Emilia solved, we can first add 19 and 76 to get:

19 + 76 = 95

Next, to find how many problems Emilia got correct out of the total, we can use the number of problems correct (19) and divide it by the total number of problems (95) to get:

19 ÷ 95 = 0.2

Finally, to make 0.2 a percentage, we can multiply it by 100 to get:

0.2 X 100 = 20

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4 0
2 years ago
Find the number of subsets of the set {1, 2, 3, ..., 9}
Irina18 [472]

Answer:

512

Step-by-step explanation:

the number of subsets of the set {1, 2, 3, ..., 9} is : 2^9 = 512

6 0
2 years ago
Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF
drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD    and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

\therefore m\angle A = m\angle B ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

m\angle F=m\angle E=90\° ⇒2

Now In △ABE and △CBF

∠A = ∠C   (from 1)

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So by A.A. similarity postulate;

△ABE∼△CBF

7 0
3 years ago
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