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3 years ago

Please tell me which ones are balanced and unbalanced!

Chemistry

1 answer:

In-s [12.5K]3 years ago

5 0

1. yes
2.yes
3.no
4.no
5.no
6.yes
7.no
8.no
9.yes
10.no
11.no
12.no
13.yes
14.no
15.yes

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Stells [14]

The answer is the first bubble, it absorbs white light and refracts green, this is because the color you see is the reflection of the object

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3 years ago

What is the pH of a solution with (H+) = .01 M? Show your work.

slamgirl [31]

Answer:

pH=2

Explanation: pH= −lg([H+]) = -lg([0,01]) = 2

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3 years ago

A 6.32-l football is filled with air at 1.90 atm. the volume of the football is reduced to 3.49 l what is the pressure of the ba

arsen [322]

You can use the formula P1V1= P2V2

(1.90)(6.32L)=P1(3.49 L).

Solve for the unknown.

P1= 3.44 atm

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4 years ago

A gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the con

sladkih [1.3K]

Answer:

$\boxed {\boxed {\sf 2. \ 157 \ kPa}}$

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using <u>Boyle's Law.</u> This states that the pressure is inversely proportional to the volume. The formula is:

$P_1V_1=P_2V_2$

We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.

$275 \ kPa *20.0 \ L=P_2V_2$

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

$275 \ kPa *20.0 \ L=P_2* 35.0 \ L$

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

$\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}$

$\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2$

The units of liters cancel.

$\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2$

$\frac {5500}{35.0} \ kPa= P_2$

$157.142857 \ kPa=P_2$

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

$157 \ kPa= P_2$

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.

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3 years ago

What is the area called in which the electrons are found ?

ehidna [41]

Answer:

orbitals

Explanation:

4 0

3 years ago