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Aleks [24]
4 years ago
12

Calculate the solubility (in M) of cobalt(II) hydroxide, Co(OH)2(s) in H2O. Ksp = 1.10×10-16 at a specific temperature.

Chemistry
1 answer:
AfilCa [17]4 years ago
5 0

Answer:

3.018 x 10⁻⁶ M.

Explanation:

  • Co(OH)₂ dissociates in solution according to the equation:

<em>Co(OH)₂ → Co²⁺ + 2OH⁻.</em>

∵ Ksp = [Co²⁺][OH⁻]² = (s)(2s)² = 4s³.

∴ 4s³ = 1.10 x 10⁻¹⁶.

∴ s³ = 1.10 x 10⁻¹⁶/4 = 2.75 x 10⁻¹⁷.

<em>∴ s</em> = ∛(2.75 x 10⁻¹⁷) = <em>3.018 x 10⁻⁶ M.</em>

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