Answer:
2 moles of SO₂
Explanation:
Equation of reaction
H₂S + 3H₂SO₄ → 4H₂O + 4SO₂
From the equation of reaction above,
1 mole of H₂S will produce 4 moles of SO₂
1 mole of H₂S = 4 moles of SO₂
0.5moles of H₂S = zmoles of SO₂
z = (0.5*4) / 1
z = 2 moles of SO₂
0.5 moles of H₂S will produce 2 moles of SO₂
There really isn't a difference if you think about it
3 Carbon Atoms and 8 Hydrogen atoms
Answer:
[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)
Explanation:
1. Molarity = moles solute / Volume solution in Liters
=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH
=> volume of solution (assuming density of final solution is 1.0g/ml) ...
volume solution = 9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution
Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH
2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)
From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln
= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.
