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3 years ago

What is the intersection of the lines y=4x+1 and y= -2x + 4

Mathematics

1 answer:

Alecsey [184]3 years ago

8 0

Answer:

The intersection is point is (1/2 , 3)

Step-by-step explanation:

y = 4x + 1

y = -2x + 4

Next, move the x's to the side of the y's and change the positive to negative and vice versa.

y - 4x = 1

y + 2x = 4

Then, multiply the top or bottom equation by -1

-y + 4x = -1

y + 2x = 4

y - 4x = 1

-y - 2x = -4

Then, subtract the y or add them to erase the y's

4x = -1

2x = 4

-4x = 1

-2x = -4

Next, add or subtract the x's and what they equal

6x = 3

-6x = -3

Then, find x

3/6x = 1/2

-3/-6x = 1/2

x = 1/2

Finally, substitute 1/2 into one of the 2 equation

y= 2+1

y = 3

y = -1 +4

y = 3

and get the point of (1/2 , 3)

Thanks for the Question

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Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

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<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

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<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

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This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

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Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

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The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

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Answer:

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