Answer:
B. 1 6 3
Explanation:
Given function definition for calc:
void calc (int a, int& b)
{
int c;
c = a + 2;
a = a * 3;
b = c + a;
}
Function invocation:
x = 1;
y = 2;
z = 3;
calc(x, y);
cout << x << " " << y << " " << z << endl;
- Since x is passed by value, its value remains 1.
- y is passed by reference to the function calc(x,y);
Tracing the function execution:
c=3
a=3
b=c+a = 6;
But b actually corresponds to y. So y=6 after function call.
- Since z is not involved in function call, its value remain 3.
So output: 1 6 3
The question above has multiple choices as below;
<span>a. </span>Wear aggregation.
<span>b.
</span>Wear mitigation.
<span>c. </span>Wear prevention
<span>d.
</span>Wear leveling
The answer is d) Wear leveling.
This technique by some SSD controllers to increase the
memory’s lifetime is called wear leveling. The mechanism for this principle is
simple: distribute the entries for all the blocks evenly so that they will wear
out evenly. Flash controller typically manages wear leveling and uses a wear
leveling algorithm to control which physical block to use.
A common technique for remembering the order<span> of </span>operations<span> is the abbreviation "PEMDAS", which is turned into the phrase "Please Excuse My Dear Aunt Sally". It stands for "Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction".</span>
Answer:
The answer IS digital convergence.
Explanation:
