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sveta [45]
3 years ago
12

7:45am is the same as which of the following military times

Mathematics
2 answers:
Sonja [21]3 years ago
5 0

Answer:

7:45 is the answer. If it pm, then the answer would be 19:45

Arlecino [84]3 years ago
5 0

07:45 am is the same as 07:45 in military time

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1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than
zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 3, n = 8

$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)

           $=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)

           $=\left(\frac{81}{11} , \frac{-43}{11}\right)

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 7, n = 1

$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)

           $=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)

           $=\left(\frac{136}{8} , \frac{-12}{8}\right)

C(x, y) = (17, –1.5)

8 0
3 years ago
What are the solutions to the equation y2 – 1 = 48?
Furkat [3]

{y}^{2}  - 1 = 48 \\  {y}^{2}  = 49 \\ y =  \sqrt{49}  \\ y =  - 7 \: or \: 7

{y}^{2}  - 1 = 24 \\  {y}^{2}  = 25 \\ y =  \sqrt{25}  \\ y =  - 5 \: or \: 5

Hope this helps. - M
6 0
3 years ago
What is the value of x?
Svetllana [295]

Answer:

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Step-by-step explanation:

ΔTRQ is an isosceles right triangle, so if we find the value of RT then the value of 'x' will be the same

We can find RT by creating a proportion based on the ratio of sides in a 30-60-90° triangle which, respectively, is 1 : \sqrt{3} : 2

2\sqrt{3}/RT = \sqrt{3}/2

cross-multiply:

\sqrt{3}· RT = 4\sqrt{3}

RT = 4

Therefore, x = 4

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kotykmax [81]

I think this is the function

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Tamiku [17]

Answer: 700

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