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3 years ago

Midpoint of R(-4,3) and S(5,6)

Mathematics

1 answer:

nirvana33 [79]3 years ago

5 0

Answer:

(0,4.5)

Step-by-step explanation:

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For what value of B is the trigonometric function considered an odd function? y=cosB(x-c)

vichka [17]

For what value of B is the trigonometric function considered an odd function? y=cosB(x-c)

1/4

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3 years ago

What is the product?

ZanzabumX [31]

Answer:

The product is:

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

$\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]$

$1 \times 2 + 3 \times 3 + 1 \times -2 = 15$

So the value of the element in the position $a_{11}$ is 15

$1 \times -2 + 3 \times 5 + 1 \times 1 = 14$

So the value of the element in the position $a_{12}$ is 14

Then with these two values you can determinate the result matrix.

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

3 0

3 years ago

What is the value of the expression when c = 4 c/2

Grace [21]

Answer:

Step-by-step explanation:

Plug in 4 for c.

(c³)/2 = (4³)/2

First, solve the parenthesis, then divide. Multiply:

4³ = 4 * 4 * 4 = 16 * 4 = 64

Next, divide:

64/2 = 32

32 is your answer.

7 0

4 years ago

DO Tuesday Write 1,003,498 in each form. Word: Expanded: need help really please

alukav5142 [94]

word form: one million, three thousand, four hundred ninety eight

number form : 1,003,498

expaned form 1000000 + 30000 + 400 + 90 + 8

i would so base form but i cant

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2 years ago

1500/semiannual period for 6 years at 2.5%/year compounded semiannually

kari74 [83]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannual, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500\left(1+\frac{0.025}{2}\right)^{2\cdot 6}\implies A=1500(1.0125)^{12}\implies A\approx 1741.13$

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3 years ago