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3 years ago

Let m = 4 and n = 5

Mathematics

2 answers:

Eva8 [605]3 years ago

8 0

<span>D. 2n but im sorry im wrong</span>

finlep [7]3 years ago

4 0

the answer is c because 4(4)+4(5)=36 and 2(4)^2=16 that 36-16=20 and mn (4*5)=20 so that gives you answer c

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A study indicates that 62% of students have have a laptop. You randomly sample 8 students. Find the probability that between 4 a

Scrat [10]

Answer:

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A study indicates that 62% of students have have a laptop.

This means that $n = 0.62$

You randomly sample 8 students.

This means that $n = 8$

Find the probability that between 4 and 6 (including endpoints) have a laptop.

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157$

$P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815$

$P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297$

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269$

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

3 0

3 years ago

49/10 as a mixed number

Anni [7]

⇒ $\frac{49}{10}$

$\frac{49}{10}$ is a improper fraction.
$\frac{49}{10}$ as a mixed number would be 4 $\frac{9}{10}$

⇒10 x 4 = 40
⇒40 + 9 = 49

$\frac{49}{10}$ = 4 $\frac{9}{10}$

⇒ANSWER = 4 $\frac{9}{10}$

7 0

3 years ago

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A snack stand sold hot dogs and chips at a recent game. The hot dogs cost $2.50 and the snacks cost $0.75. After the game, they

zalisa [80]

Answer:

this is correct on edge

Step-by-step explanation:

6 0

3 years ago

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helppppp please what is it