2 years ago

Please help me with question 16 and question 17 . Thank you

Physics

1 answer:

liberstina [14]2 years ago

7 0

Answer:

JADGLHYKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKkkkkkkkkkkkk

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ANOTHER PHYSICS QUESTION PLEASE HELP!

Sergio039 [100]

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3 years ago

What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per

Brilliant_brown [7]

Answer:

$a_{cp}=7.77m/s^2$

Explanation:

The equation for centripetal acceleration is $a_{cp}=\frac{v^2}{r}$ .

We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.

Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference $C=2\pi r$ and the period T, then we have:

$v=\frac{C}{T}=2\pi r f$

Putting all together:

$a_{cp}=\frac{(2\pi r f)^2}{r}=4 \pi^2f^2r=4 \pi^2(0.75Hz)^2(0.35m)=7.77m/s^2$

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3 years ago

What do odometer and speedometer read ?

maksim [4K]

Odometer: tells you the distance traveled by vehicle since it was new (or when last reset)

Speedometer: tells you the velocity of the vehicle at that moment.

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Which item could you use in place of an ammeter to demonstrate that a

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2 years ago

If i have no swag and i dab what happens

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You earn swag points.