Let
A = the amplitude of vibration
k = the spring constant
m = the mass of the object
The displacement at time, t, is of the form
x(t) = A cos(ωt)
where
ω = the circular frequency.
The velocity is
v(t) = -ωA sin(ωt)
The maximum velocity occurs when the sin function is either 1 or -1.
Therefore

Therefore

The KE (kinetic energy) is given by

The PE (potential energy) is given by

When the KE and PE are equal, then

For the oscillating spring,

Therefore

Answer:
I think Y is the answer to number 4
1 meter up, 1 meter to the left and then 1 metter down.
It goes 1 meter up and 1 meter down, so its in the same place. The only displacement is
1 meter to the left.
Look at picture:
(hope this helps)
Answer:
option c is correct
Explanation:
we know that
2as=vf^2-vi^2
vf=24 m/s
vi= 0 m/s
a=g= 9.8 m/s^2
s=vf^2-vi^2/2a
s=(24)²-(0)²/2*9.8
s=576/19.6
s=29.4 m
therefore option c is correct