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torisob [31]
3 years ago
7

Which "sphere" does an astronomer most directly study?

Physics
2 answers:
Allushta [10]3 years ago
7 0

Answer:

exosphere

Explanation:

exosphere is space

astronomy is space

Lisa [10]3 years ago
5 0
I would choose B. exosphere. Astronomers study outer space, planets and ect.
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Should i make my pet shark bark like a dog woof woof​
mr_godi [17]

Answer: YES !!

Explanation:  THAT WOULD BE AMAZING!!!

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3 years ago
Which pair of triangles can be proven congruent by the hl theorem?
hoa [83]

The pairs of triangles that can be proven congruent by the hl theorem is the right angled triangle.

<h3>What is mearnt be the HL theorm?</h3>

The HL theorem is also known as the Hypothenus Leg theorem, it states that "the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent."

Learn more about the postulates of the HL theorem here:

brainly.com/question/25922842

4 0
2 years ago
Am 1 years old UwU (JK 15)
igomit [66]

Answer:

so am i ._. 15 not 1 ofc lol

Explanation:

7 0
2 years ago
A greyhound's velocity changes from 10 meters per second to 15 meters per second in 0.5 second. What is the greyhound's average
Elden [556K]

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4 0
3 years ago
A submarine is 2.84 102 m horizontally from shore and 1.00 102 m beneath the surface of the water. A laser beam is sent from the
xxMikexx [17]

Answer:

468 m

Explanation:

So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.

The length CE is length AE - length AC = 284 - 234 = 50 m

We can calculate the angle ECD:

tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2

\hat{ECD} = tan^{-1} 2 = 63.43^o

This is also the angle ACB, so we can find the length AB:

tan(\hat{ACB}) = \frac{AB}{AC} = \frac{AB}{234}

2 = \frac{AB}{234}

AB = 2*234 = 468 m

So the height of the building is 468m

5 0
3 years ago
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