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kramer
3 years ago
5

3 objects that have gravitational potential energy?

Physics
2 answers:
WITCHER [35]3 years ago
8 0
When an object is above the Earth's surface it has gravitational potential energy (GPE). The amount of GPE an object has depends on its mass and its height above the Earth's surface.
The weight of an object is the size of the force of gravity pulling the object down. When an object falls it transfers GPE to KE (kinetic energy).
sleet_krkn [62]3 years ago
3 0
The water in the tank above the buildings
The fruits on the tree
Something like a cup or a book or a laptop on the table
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snow_lady [41]

Answer:

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Explanation:

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8 0
3 years ago
A hiker walks 9.4 miles at an angle of 60° south of west. Find the west and south components of the walk. Round your answers to
Tanzania [10]

Answer:

The west axis component of walk is, A = 5 miles

The east axis component of walk is, B = 8 miles

Explanation:

Given data,

The displacement of hiker south of west, R = 9.4 miles

The angle formed south of west, Ф = 60°

The vector components along,

                   the west axis is

                                      A = R cosФ

                                       A = 9.4 x cos 60

                                       A = 4.7 miles

                                        A = 5 miles

The west axis component of walk is, A = 5 miles

                    the south axis is

                                      B = R sinФ

                                       B = 9.4 sin 60

                                        B = 8.14 miles

                                         B = 8 miles

The east axis component of walk is, B = 8 miles

4 0
3 years ago
What is the amplitude of an AC voltage waveform, in units of Volts, if the RMS value is 369 V?
Blizzard [7]

Answer:

521.8 V

Explanation:

The RMS value of the voltage of an AC signal is given by

V_{rms}=\frac{V_0}{\sqrt{2}}

where

V_0 is the peak voltage, which corresponds to the amplitude of the AC waveform

In this problem, we know the RMS voltage

V_{rms}=369 V

Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):

V_0 = \sqrt{2}V_{rms}=\sqrt{2}(369 V)=521.8 V

4 0
3 years ago
URGENT! PLEASE ANSWER!!
Marrrta [24]

Answer:

C

Explanation:

The answer is obvious from the given figure

7 0
3 years ago
Please help ASAP please ASAP
alina1380 [7]
The answer to your question is 185
5 0
3 years ago
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