All categories

3 years ago

An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work

Physics

1 answer:

amid [387]3 years ago

6 0

Answer:

Its answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

You might be interested in

A person walks 13 km in 2.0 h. What is the person's average velocity in km/h and<br>m/s?

murzikaleks [220]

13/2 = 6.5 Km/h
That’s 6500/3600= 1.8 m/s

3 0

3 years ago

Which does a reference point provide? Select two options. a position from which to measure future distance a set of standard uni

In-s [12.5K]

Answer:

hope this helps you :)

Explanation:

An object is in motion if its position changes relative to another object. To decide if you are moving, you can use your chair as a reference point. A reference point is a place or object used for comparison to determine if something is in motion.

4 0

4 years ago

A spacecraft is on a journey to the moon. At what point, as measured from the center of the earth, does the gravitational force

Alexeev081 [22]

Answer:

This distance is measured from the center of the earth r = 3.4 10⁸ m

Explanation:

The equation for gravitational attraction force is

F = G m1 m2 / r²

Where g is the universal gravitation constant, m are the masses of the body and r is the distance between them, remember that this force is always attractive

Let's write the sum of force on the ship and place the condition that is balanced

F1 -F2 = 0

F1 = F2

Let's write this equation for our case

G m Me / r² = G m Mm / (r'.)²

The distance r is measured from the center of the earth and the distance r' is measured from the center of the moon,

r' = 3.85 10⁸ m

Let's simplify and calculate the distance

Me / r² = Mm / / (3.85 108- r)²

Me / Mm (3.85 108- r)² = r²

√ 81.4 (3.85 108 -r) = r

√ 81.4 3.85 108 = r (1 + √ 81.4)

34.74 108 = r (10.02)

r = 34.74 10⁸ / 10.2

r = 3.4 10⁸ m

This distance is measured from the center of the earth

6 0

4 years ago

El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La

allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

$\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta$

En donde:

$\omega_{f}$ : es la velocidad angular final = 2000 rpm = 209,4 rad/s

$\omega_{0}$ : es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.

Resolviendo la ecuación (1) para α, tenemos:

$\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}$

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.

b) El tiempo transcurrido se puede encontrar como sigue:

$\omega_{f} = \omega_{0} + \alpha t$

Resolviendo para t, tenemos:

$t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s$

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0

3 years ago

Find the wavelength of the balmer series spectral line corresponding to n = 15.

Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

= 1.097 × 10⁷ m⁻¹(1/4 -1/225)

= 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

= 1.097 × 10⁷ m⁻¹ 0.245556

= 2.693 10⁶ m⁻¹

So,

λ = 1/2.693 10⁶ m⁻¹

= 0.3712 10⁻⁶ m

= 371.2 mm

7 0

3 years ago