C is the answer to your question!
Answer:
V(car) = V(truck) at t = Dt/2
acceleration = v(car) = D/t^2
Explanation:
acceleration = v(car) = D/t^2
Since the average velocities must be the same, the car's final velocity must be twice the trunk velocity assuming the car start with zero velocity, since acceleration remain the same throughout the journey velocities at half-time point must be equal.
Answer:
Option B (1.51 m)
Explanation:
U 2 can help me by marking as brainliest........
Answer:
In both cases the height is greater than 10.3 m
Explanation:
Pressure is defined by the relationship
P = F / A
in this case the force is the weight of the two gases
F = W = m g
If we use the definition of density
ρ = m / V
V = A h
m = ρ A h
we substitute
P = ρ g h
h = 
For this case the density of the gases is
ρ' = 0.9
h =
we calculate
ρ’= 0.9 \rho_{water}
h = 1 105 / (0.9 1000 9.8)
h = 11.3 m
ρ’= 0.8 \rho_{water}
h = 1 105 / (0.8 1000 9.8
h = 12.8 m
In both cases the height is greater than 10.3 m