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Aleonysh [2.5K]
3 years ago
13

Which trigonometric ratios are correct for triangle DEF?

Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0
Sin(D) = 24/25
tan(D) = 24/7
sin(E) = 7/25 
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J18 IXL NOW BEFORE TODAYY
Stella [2.4K]

Answer:

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Step-by-step explanation:

Free pionts thx

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3 years ago
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From 1980 to 1990, the consumer price index (CPI) increased from 82.4 to 130.7. If a gallon of apple juice cost $0.95 in 1980 an
ryzh [129]
Answer: C $1.51

To solve this, start with a proportion. Put the CPI numbers on the left and the apple juice prices on the right.

You will have:

82.4/130.7 = 0.95/x

Cross multiply to solve and you will get the price of the juice is $1.51.
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3 years ago
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GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m
Harrizon [31]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 3.50 mg  

     Alternate Hypothesis, H_A : \mu > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average mg of mercury in compact fluorescent bulbs.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, H_A : \mu > 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mg of mercury = 3.59

            \sigma = population standard deviation = 0.18 mg

            n = sample of bulbs = 25

So, <em><u>test statistics</u></em>  =  \frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }

                               =  2.50

The value of z test statistics is 2.50.

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.50) = 1 - P(Z \leq 2.50)

                                             = 1 - 0.9938 = 0.0062

<em />

<em>Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0
2 years ago
2, -2, 2, -2, common ratio
adelina 88 [10]
To get -2 from 2, you would multiple by -1.

To get 2 from -2, you also would multiple by -1.

Ad infinitum.

So the common ratio is -1.

Hope this helps.
8 0
3 years ago
What is the approximate distance between points D and E? Round your answer to the nearest hundredth.
kenny6666 [7]

Answer:

I want to say its C - 8.12 units. But I think it could also be D- 8.25 units. Just not 100% sure.

6 0
3 years ago
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