Answer:
Choice B
Step-by-step explanation:
The first step is to write the polar equation of the conic section in standard form by dividing the numerator and denominator by 6;
The eccentricity of this conic section is thus 2/3, the coefficient of cos theta. Clearly, the eccentricity is between o and 1 implying that this conic section represents an Ellipse.
Lastly, the ellipse will open towards the left since we have positive cos theta in the denominator. The only graph that meets the conditions is graph B.
<span>The y-intercept of a function is given by the initial value of a function. It is the value of the function when x = 0.
Given the functions
A. Blake is tracking his savings account with an interest rate of 5% and a original deposit of $6.
The y-intercept for this function is the initial deposit which is $6.
B.
x g(x)
0 6
1 2
2 10
The y-intersept for this function is 6 which isthe value of the function g(x) when x = 0.
C. The function h of x equals 4 to the x power, plus 3
When x = 0,
Thus the y-intecept is 4.
D. j(x) = 10(2)^x
when x = 0,
Thus, the y-intercept is 10.
Thereforen the function with the highest y-intercept is
which has a y-intercept of 10.
</span>
(5x⁴ - 3x³ + 6x) - (3x³ + 11x² - 8x)<span>
</span>Expand the second bracket by multiplying throughout by -1
5x⁴ - 3x³ + 6x - <span>3x³ - 11x² + 8x
</span>
Group like terms and simplify
5x⁴ - 3x³ - 3x³ - 11x² + 6x <span>+ 8x
</span>5x⁴ <span>- 6x</span>³ - <span>11x² + 14x</span>
