X+79=98 (subtract 79 to isolate x)
X=19 so it is false
Answer:
As the least common multiple of two numbers is 60 , the two numbers are factors of 60 . Among {1,2,3,4,5,6,10,12,15,20,30,60} , 3 & 10 and 5 & 12 are the only two pair of numbers whose difference is 7 . But Least common multiple of 3 and 10 is 30
Answer:
128
Step-by-step explanation:
You would multiply 79 by 1.62 to get the answer.
This would give you 127.98 which you would round up to 128.
Answer:
There seems to be a typo error but still this has solution.
Let the number be = x
A positive real number is 6 less than another. Means the second will be 
The sum of the square of the two numbers is 38.
=> 
=> 
=> 
=> 
Taking out 2 common;
=> 
Solving this quadratic equation, we get;
and 
As positive number is needed, we have
or x = 
x = 0.162277
And other number is 6.162277.