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3 years ago

-3/4^-4 what is the answer. i need to know the answer.

Mathematics

2 answers:

evablogger [386]3 years ago

8 0

Answer:

-12.4

Step-by-step explanation:

borishaifa [10]3 years ago

5 0

Greetings! Hope this helps!

Answer

Fraction -(3/4)^-4

Decimal -3.160494

Have a good day!

_______________

A brainliest would help tons! :D

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The answer is:

c = 7s

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2 years ago

The pharmacist uses 67mg, 100g and 0.6 kg of drug to compound 3 separate precription. how much total drug did the pharmacist use

FromTheMoon [43]

Answer: 700.067 g

Step-by-step explanation:

Given : The pharmacist uses 67mg, 100g and 0.6 kg of drug to compound 3 separate prescription.

We know that 1 gram= 1000 milligram

and 1 kilogram = 1000 grams

Then, By UNITARY METHOD, $\text{1 mg}=\dfrac{1}{1000}\text{ gram}$

Now, We convert each amount of drug into grams as ,

$67\ mg=67\times\dfrac{1}{1000}\ g\\\\=0.067\text{ g}$

AND

$0.6\ kg=0.6\times100=60\text{ g}$

Now, the total drug used by Pharmacist (in grams) = $0.067+100+600=700.067\ g$

Hence, Pharmacist used 700.067 g of total drug.

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2 years ago

Why are these two angles congruent?

Stella [2.4K]

What angels? You need to show a picture :)

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3 years ago

Read 2 more answers

Ok last question i asked was answered by a scam bot so here i go again

Daniel [21]

Answer:

Make 7 jumps, each 0.2 units long. You end at 1.4, which is the product of 7 and 0.2.

Sorry to hear about the bot! Hope this helps!

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2 years ago

How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4)

saveliy_v [14]

<h3>Solution:</h3>

$\rightarrow\sf((p(x) {x}^{2} + 2x + 4)( {x}^{2} + 2x + 4)) \\ = \sf {ax}^{2} + bx + c \\ = \sf(p(x) {x}^{2} {x}^{2} + p(x) {x}^{2} (2x) + p(x) {x}^{2} \times 4 + 2x \times {x}^{2} + 2x(2x) + 2x \times 4 + {4x}^{2} + 4(2x) + 4 \times 4) \\ = \sf( {x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16) \\ \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

<h3>Answer:</h3>

$\large\boxed{\sf{\red{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

$\color{red}{==========================}$

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2 years ago