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ahrayia [7]
3 years ago
14

1. The rapper charges a fee of $200 per party and $5 per song. Write an equation that

Mathematics
1 answer:
suter [353]3 years ago
8 0

Answer:

$235

Step-by-step explanation:

X= per party A= per song

X*200+5*A

He goes to a party and plays 7 songs therefore he will be paid;

200+ 5*7= $235

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Three more than twice a number r
sukhopar [10]

Answer:

2r + 3

Step-by-step explanation:

probably

8 0
3 years ago
List least to greatest 19/50, 5/12, 0.12
anyanavicka [17]
The answer 0.12, 19/50, 5/12
4 0
3 years ago
Please help me with thisss
Solnce55 [7]

Answer:

(x, y) = (-2, -3)

WORK:

2x + 4y = -16  =

-2x + 2y = -2  =

(^ the two’s cancel out) =

6y = -18  =

(^ you need to divide 6 on both sides to get just y) =

6y/6 = -18/6  =

(^ the six’s cancel out) =

y = -3  =

(^ now you have to plug this in to get x) =

2x + 4(-3) = -16  =

2x - 12 = -16  =

(^ you need to add 12 on both sides to get rid of it on the left side to add it to -16 on the right side) =

2x = -4  =

2x/2 = -4/2  =

(^ now you divide 2 on both sides again to get just y, and they will cancel out) =

x = -2  =

THEREFORE YOU GET (-2, -3)

4 0
3 years ago
Llana ran 2 laps around the field in 8 minutes. what was he average speed
son4ous [18]

Answer: 1 Lap Per Every 4 Minutes Is Her Average Speed.

Step-by-step explanation: To find her average speed, simply divide 8 by 2 which is 4.

8/2 = 4 minutes per lap.

3 0
3 years ago
This question refers to unions and intersections of relations. Since relations are subsets of Cartesian products, their unions a
Mice21 [21]

Answer:

AXB= = {(x, y) ∈ A ✕ B| x ∈ A , y ∈  B}

R= {(x, y) ∈ A ✕ B| x R y ⇔ |x| = |y|}

S={(x, y) ∈ x A ✕ B | S y ⇔ x − y is even}

R ∪ S= {(x, y) ∈ A ✕ B | (x, y) ∈ R or (x, y) ∈ S}

R ∩ S = {(x, y) ∈ A ✕ B | (x, y) ∈ R and (x, y) ∈ S}

Step-by-step explanation:

Let A = {−4, 4, 7, 9} and B = {4, 7},

Then A X B= { (-4,4),(-4,7),(4,4),(4,7),(7,4),(7,7),(9,4),(9,7)}

AXB contains all elements of A and B such that x from A and y is from B.

AXB= = {(x, y) ∈ A ✕ B| x ∈ A , y ∈  B}

R= {(-4,4),(4,4),(7,7)}

R consists all ordered pairs where  |x| = |y|

R= {(x, y) ∈ A ✕ B| x R y ⇔ |x| = |y|}

S= { (-4,4),(4,4),(7,7)}

S={(x, y) ∈ x A ✕ B | S y ⇔ x − y is even}

S consists all ordered pairs where x-y is even.

R ∪ S, = { (-4,4),(4,4),(7,7)}

R US is a set containing subsets of both sets R and S

R ∪ S= {(x, y) ∈ A ✕ B | (x, y) ∈ R or (x, y) ∈ S}

R ∩ S=  {(-4,4),(4,4),(7,7)}

R ∩ Sis a set containing subsets only which are common between sets R and S

R ∩ S = {(x, y) ∈ A ✕ B | (x, y) ∈ R and (x, y) ∈ S}

8 0
3 years ago
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