If we use the width as x we have 2x with both widths and 4x with both lengths. So 6x=24 and x=4. So length is 8 and width is 4.
Trapezoid
quadrilateral
rhombus
parallelogram
X=numbers of hammers
y=numbers of scewdrivers
f(x,y)= total cost in $
f(x,y)=11x+6.65y
f(4,7)=4(11)+6.65(7)=44+46.55=90.55
Sol: an expresion for the total cost of the tools is f(x,y)=11x+6.65 y;
x=number of hammers
y= number of scewdrivers.
The total cost is $90.55
The answer for the problem is 5, 12
We can't tell from the graph whether the left point of each step is included, or the right point. If the left, this is a graph of
y = 7 + floor(x)
