<h2>1)</h2>
This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.
<h2>2)</h2>
Well he started off correct to the point of completing the square.
Answer:
-11x-3y^2
Step-by-step explanation:
(8x^2-9x^2-4x)+(x^2-3y^2-7x)
-x^2-4x+x^2-3y^2-7x
-4x-7x-3y^2
-11x-3y^2
Answer:
1/x-2/3=3/2x
-2/3=3/2x-1/x
-2/3=(3-2)/2x
-2/3=1/2x
by cross multiplication
-2(2x)=1(3)
-4x=3
x= -3/4
Step-by-step explanation:
I hope this will help
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