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VashaNatasha [74]
3 years ago
13

Which relationships have the same constant of proportionality between yyy and xxx as the following table? xxx yyy 444 323232 777

565656 888 646464 Choose 3 answers: Choose 3 answers:
Mathematics
2 answers:
Nataly [62]3 years ago
7 0
Which relationships have the same constant of proportionality between yyy and xxx as the following table? xxx yyy 444 323232 777 565656 888 646464 Choose 3 answers: Choose 3 answers:
Tcecarenko [31]3 years ago
7 0

Answer:

a,c, and d

Step-by-step explanation: got it on khan

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Consider the function,
RUDIKE [14]

Answer:

If x= 4 then f(x) = 4x -5 is 11.

Step-by-step explanation:

f(x) = 4x -5

We need to find the domain value that corresponds to the output f(x) = 11

In this question, we need to solve the expression for value of x such that the answer is 11.

if  x= 3

f(3) = 4(3) -5

     = 12 -5

    = 7

Since we want the answer 11 so we cannot take x= 3

if x = 4

f(4) = 4(4)-5

    = 16 - 5

    = 11

So, if x= 4 then f(x) = 4x -5 is 11.

5 0
3 years ago
Hii darling pls help !!<3
saul85 [17]

Answer:

Hello! answer: y = 76

Because there vertical angles they Will have the same measure therefore y = 76 Hope that helps!

6 0
3 years ago
Arrange these numbers from least to greatest 2/5 5/7 4/9
mr Goodwill [35]
4/9 2/5 5/7 is sorted from least to greatest

4 0
3 years ago
Read 2 more answers
A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u
USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

So

\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

So

\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314

Distribution of the difference:

Mean:

\mu = \mu_A - \mu_B = 36 - 42 = -6

Standard error:

s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = zs = 1.96*1.4142 = 2.77

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0
3 years ago
Dr. Jones deposited $500 into an account that ears 6% simple interest. How many years will it take for the value of the account
Mekhanik [1.2K]

Answer:

50 years

Step-by-step explanation:

Given data

Principal= $500

Rate= 6%

Amount = $2000

The simple interest expression is given as

A=P(1+rt)

Substitute

2000= 500(1+0.06*t)

open bracket

2000=500+ 30t

2000-500=30t

1500=30t

t= 1500/30

t= 50 years

Hence the time is 50 years

5 0
3 years ago
Read 2 more answers
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