Ask question

Ask question

All categories

3 years ago

14

-6(a+8) simple expression

1 answer:

USPshnik [31]3 years ago

4 0

-6a - 48 This answer should be correct

You might be interested in

50 POINTS PLZZZZZ HELP NOW I NEED FULL EXPLANATION AND RIGHT ANSWERS

lisov135 [29]

The side lengths could be 4 in. x 16 in. because that equals 64 inches^2. It could also be 8 in. x 8 in. because that also equals 64 inches^2.

4 0

3 years ago

Read 2 more answers

a store is offering a 20% discount on all sales over $50 if you purchase a shirt and a pair of jeans for $62.50, what is the amo

kaheart [24]

Discount = 20% of the product price
Discount = 20/100 × $62.50
Discount = $12.5

8 0

2 years ago

Read 2 more answers

the sum of ones digit and tens digit is also 10. However, my ones digit is greater than my tens digit. i am a prime number less

Naddik [55]

The number that would fit is 37.

7 0

3 years ago

mrs corner makes a venn diagram on the subjects her students want to take. what is the probability a student wants to music and

nikklg [1K]

Step-by-step explanation:

A famer wants to divide 8085 ha of grazing into 9 or 15 cramp of equal size

4 0

2 years ago

Simplify using only POSITIVE exponents:

pickupchik [31]

So here are a few rules with exponents that you should know:

Multiplying exponents of the same base: $x^m*x^n=x^{m+n}$
Dividing exponents of the same base: $x^m\div x^n=x^{m-n}$
Powering a power to a power: $(x^m)^n=x^{m*n}$
Converting a negative exponent to a positive one: $x^{-m}=\frac{1}{x^m}\ \textsf{and}\ \frac{1}{x^{-m}}=x^m$

<h2>1.</h2>

Firstly, solve the outside exponent:

$(2x^3y^7)^{-2}=2^{-2}x^{3*-2}y^{7*-2}=2^{-2}x^{-6}y^{-14}$

Next, convert the negative exponents into positive ones:

$2^{-2}x^{-6}y^{-14}=\frac{1}{2^2x^6y^{14}}=\frac{1}{4x^6y^{14}}$

<u>Your final answer is $\frac{1}{4x^6y^{14}}$ </u>

<h2>2.</h2>

For this, just divide:

$\frac{12x^5y^3}{4x^{-1}}=\frac{12}{4}x^{5-(-1)}y^{3-0}=3x^6y^3$

<u>Your final answer is $3x^6y^3$ </u>

<h2>3.</h2>

For this, convert all negative exponents into positive ones:

$\frac{r^{-7}b^{-8}}{t^{-4}w}=\frac{t^4}{r^7b^8w}$

<u>Your final answer is $\frac{t^4}{r^7b^8w}$ </u>

3 0

3 years ago