Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
77 percent of 149 is 114.73
Answer: Domain: (-∞, 0) U (0, ∞)
Step-by-step explanation:
Domain: (-∞, 0) U (0, ∞)
Answer:
Follow the steps I did in the explanation.
Step-by-step explanation:
It says to evaluate the equation :-
3.2 = 4/5(b - 5)
3.2 = (4/5 × b) + (4/5 × -5)
3.2 = 4/5b - 4
3.2 + 4 = 4/5b
5/4 × 7.2 = b
9 = b
Hope this helps, thank you :) !!
